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5p^2-36p+36=0
a = 5; b = -36; c = +36;
Δ = b2-4ac
Δ = -362-4·5·36
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-24}{2*5}=\frac{12}{10} =1+1/5 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+24}{2*5}=\frac{60}{10} =6 $
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